Jawaban:
[tex]x = - 3 + \sqrt{13} \: atau \: x = - 3 - \sqrt{13} [/tex]
Penjelasan dengan langkah-langkah:
[tex] \frac{(x - 2)}{(x + 2)} = \frac{(x + 1)}{ ( - 3)} \\ (x - 2)( - 3) = (x + 2)(x + 1) \\ - 3x + 6 = {x}^{2} + x + 2x + 2 \\ 0 = {x}^{2} + 3x + 3x + 2 - 6 \\ 0 = {x}^{2} + 6x - 4 \\ \\ x = \frac{ - b ± \sqrt{ {b}^{2} - 4ac } }{2a} \\ x = \frac{ - 6± \sqrt{ {6}^{2} - 4.1.( - 4)} }{2} \\ x = \frac{ - 6± \sqrt{52} }{2} \\ x = \frac{ - 6± 2 \sqrt{13} }{2} \\ x = - 3 + \sqrt{13} \: atau \: x = - 3 - \sqrt{13} [/tex]
[tex] \frac{(x - 2)}{(x + 2)} = \frac{(x + 1)}{( - 3)} [/tex]
[tex](x - 2)( - 3) = (x + 2)(x + 1)[/tex]
[tex] - 3x + 6 = {x}^{2} + x + 2x + 2[/tex]
[tex] - 3x + 6 = {x}^{2} + 3x + 2[/tex]
[tex] - {x}^{2} - 3x - 3x + 6 - 2 = 0[/tex]
[tex] - {x}^{2} - 6x + 4 = 0[/tex]
[answer.2.content]
